Online coding and AI classes in the Apurímac region

The free class is also an honest assessment. The mentor sets a simple task in easy English and watches how the learner manages. If English stands in the way for now, we will tell you and suggest private lessons, a later start or a different course. Spanish-speaking parents can read a guide to coding classes for children written in Spanish, and learners curious about doing both at once can see coding and English together.

import csv
import math

with open("ie-apurimac.csv", encoding="utf-8-sig", newline="") as f:
    rows = list(csv.DictReader(f, delimiter=";"))

def centre(district):
    pts = [(float(r["latitud"]), float(r["longitud"])) for r in rows if r["nom_dist"] == district]
    return sum(p[0] for p in pts) / len(pts), sum(p[1] for p in pts) / len(pts)

def km(a, b):
    dlat, dlon = b[0] - a[0], b[1] - a[1]
    h = math.sin(dlat / 2) ** 2 + math.cos(a[0]) * math.cos(b[0]) * math.sin(dlon / 2) ** 2
    return 2 * 6371 * math.asin(math.sqrt(h))

abancay = centre("ABANCAY")
far = max(km(abancay, (float(r["latitud"]), float(r["longitud"]))) for r in rows)
print("Farthest row from Abancay:", round(far), "km")

Nothing crashed, and the answer is impossible. The rows in the file span only about one and a half degrees of latitude, under 200 km from north to south, so no school can be almost 7,000 km from Abancay. The reason is units: math.sin and math.cos in Python expect radians, and Version 1 gives them degrees. Sin of 13.6 degrees is about 0.24, but math.sin(13.6) treats 13.6 as radians and returns about 0.86. The program is not wrong in a way the computer can see; only a person who asks "is this possible?" will notice.

import csv
import math

with open("ie-apurimac.csv", encoding="utf-8-sig", newline="") as f:
    rows = list(csv.DictReader(f, delimiter=";"))

def centre(district):
    pts = [(float(r["latitud"]), float(r["longitud"])) for r in rows if r["nom_dist"] == district]
    return sum(p[0] for p in pts) / len(pts), sum(p[1] for p in pts) / len(pts)

def km(a, b):
    lat1, lon1, lat2, lon2 = map(math.radians, (*a, *b))
    h = (math.sin((lat2 - lat1) / 2) ** 2
         + math.cos(lat1) * math.cos(lat2) * math.sin((lon2 - lon1) / 2) ** 2)
    return 2 * 6371 * math.asin(math.sqrt(h))

towns = [centre("ABANCAY"), centre("ANDAHUAYLAS")]
far = max(km(towns[0], (float(r["latitud"]), float(r["longitud"]))) for r in rows)
print("Farthest row from Abancay:", round(far), "km")

near = []
for r in rows:
    if r["nivel"] == "Secundaria" and r["estado"] == "Activa":
        here = (float(r["latitud"]), float(r["longitud"]))
        near.append(min(km(t, here) for t in towns))
print("Active secundaria rows:", len(near))
print("Over 50 km from both towns:", sum(d > 50 for d in near))
print("Median distance:", round(sorted(near)[len(near) // 2], 1), "km")

Version 2 converts all four angles with map(math.radians, ...) before any trigonometry. The farthest row from Abancay is now 145 km away, which fits the size of the region. It then looks only at the 355 active secundaria rows, measures each to both towns and keeps the smaller distance with min(). Half of them are within 34.5 km of the nearer town in a straight line, and 122 are more than 50 km from both. Roads in the Andes wind, so the real journeys are longer than these lines; the numbers are a floor, not a travel time.

Data: Gobierno Regional de Apurímac, Instituciones Educativas de Apurímac, ODbL. Distances, counts and the town reference points are ours. Straight-line distances on a sphere of radius 6,371 km; actual road distances are longer.

1. For ages 6 to 8. On a map of your town, stretch a string from home to school, then lay it along the streets you really walk. Which is longer, and why?
2. Ages 8 to 11, with blocks. Make a sprite move from one point to another and count its steps along x and y. Is the straight path shorter than going across then up?
3. Ages 11 to 13. Print math.sin(30) and math.sin(math.radians(30)). Which one is 0.5, and what does the other one mean?
4. Teenagers. Add a third reference town, such as Chalhuanca in Aymaraes, using the same averaging method. How many of the 122 rows come within 50 km?
5. University and adults. Compare the haversine result with a flat-map approximation that multiplies degrees by 111 km. How large is the difference at Apurímac's latitude?

Asking "could this possibly be right?" before trusting a number is one of the most useful habits in programming, and in using AI tools. It is the habit our page on building with AI without copying keeps returning to.

MINEDU's Python initiative for secundaria, Fábrica de Programadores, started in July 2025 with 1,000 pupils in Lima Norte; we found nothing showing it in Apurímac. Every pupil in Peru can take part in contests: the ONEM maths olympiad's school round was on 8 July 2026 and drew more than 1.7 million secundaria pupils, and the OPI computing olympiads from UTEC are free. We have no link with the DRE, MINEDU, UTEC or any contest, and we teach with our own problems.

INEI, Compendio Estadístico Perú 2026 (tomo 1), cuadros 11.5, 11.6 and 11.13; data from the Encuesta Nacional de Hogares. Decimal commas printed as points.

Our suggestions only. Grade placement uses MINEDU's normative age at 31 March, so pupils in the same grade can be nearly a year apart.

For university and institute students, coding courses for university students in Peru goes further; all Peru guides are listed on coding and AI classes in Peru.

Time zones from the tz database: Peru is UTC minus 5 with no daylight saving since 1994 (America/Lima), India is UTC plus 5:30. The gap of 10 hours 30 minutes holds every day.

With no clock changes on either side, an hour chosen once is fixed for the year, and you choose it in your own time. Peru's 2026 school year opened on 16 March 2026; families often start in the January to March break, and adults whenever they are ready.