ICSE Computer Applications competency based questions, and what is actually confirmed about them.

int[] board = {6, 11, 4, 13, 9};
int total = 0, max = 0;
for (int i = 0; i < board.length; i++) {
    total += board[i];
    if (board[i] > board[max])
        max = i;
}
System.out.println("Total boarded: " + total);
System.out.println("Busiest stop: " + (max + 1));
int seats = 0, stop;
for (stop = 0; stop < board.length; stop++) {
    seats += board[stop];
    if (seats >= 30)
        break;
}
System.out.println("Bus full after stop " + (stop + 1) + " with " + seats);

Total boarded: 43
Busiest stop: 4
Bus full after stop 4 with 34

(i) A single dimensional array. (ii) 43, and stop 4 with 13; max holds an index, so the stop number is max + 1. (iii) break, which leaves the loop with stop still pointing at the stop where the bus filled. (iv) Stop 4: 6 + 11 + 4 is 21, and 13 more makes 34.

public class Planter {
    private int moisture;
    private double litres;
    Planter(int m) { moisture = m; }
    void decide() {
        if (moisture < 20)
            litres = 1.5;
        else if (moisture < 45)
            litres = 0.75;
        else
            litres = 0;
    }
    void show() {
        System.out.println("Moisture " + moisture + "%: water " + litres + " L");
    }
    public static void main(String[] args) {
        Planter p = new Planter(32);
        p.decide();
        p.show();
    }
}

Moisture 32%: water 0.75 L

// (iv)
litres = moisture < 20 ? 1.5 : moisture < 45 ? 0.75 : 0;

(i) A parameterised constructor. (ii) So no other class can set an impossible reading; this is encapsulation. (iii) 32 fails the first test and passes the second. A reading of 12 prints 1.5 L, and the ternary in (iv) gives 0.0 for 50.